Question

please 413 ................
I will nark the best answer as brainliest.....​

Answer 1

Given

• Side of a hexagon = 5 cm

To find

• Area of hexagon

Solution

In the attachment, the hexagon MNOPQR has a side of 5 cm.

Things to knoW :

• A hexagon is created with six equilateral triangles.
• So formula for finding area of hexagon is derived from formula of equilateral triangle.

As we know,

→ Area of equilateral∆ = √3a²/4 unit²

So, area of a hexagon :-

→ Area of hexagon = 6 × (√3a²/4)

→ Area of hexagon = 3(√3a²/2)

→ Area of hexagon = (3√3 a²)/2

Now findinG area of hexaGon MNOPQR :

⇒ Ar(hexagon) = [ 3√3 (5)²]/2

⇒ Ar(hexagon) = [3√3 × 25]/2

⇒ Ar(hexagon) = [75√3]/2

⇒ Ar(hexagon) = $\sf \dfrac{75}{2} \sqrt{3}\: cm^2$

Therefore,

ReQuired answer : d) (75/2)√3 cm²

Answer 2

______________________

$\huge \tt {GIVEN:}$

side of a hexagon = 5 cm

Area of hexagon

_______________________

$\huge \tt {SOLUTION:}$

As we know ,

Area of hexagon = (3√3a²)/2

In the attachment,hexagon MNOPQR has a side of 5 cm

_______________________

Area of hexagon MNOPQR =

➩[3√3(5)²]/2

➩[3√3×25]/2

➩[75√3]/2

➩75/2 √3 cm²

______________________