PLEASE ALSO ANSWER THIS QUESTION!!
Answers
Answer:
A fully charged capacitor no current draws from cell. So, no current flow in the capacitor branch and corresponding circuit is shown in figure.
Total resistance of the circuit is Rt=2.8+2∣∣3=2.8+2+32×3=2.8+1.2=4Ω
Current in the circuit is I=46=1.5A
If I1 and I2 are the current through 2Ω and 3Ω respectively, then I=I1+I2...(1)
As 2Ω and 3Ω are in parallel so V2Ω=V3Ω or 2I1=3I2⇒I2=(2/3)I1
now, (1) becomes, 1.5=I1+(2/3)I1=35I1
or I1=51.5×3=0.9A
Explanation:
mark as brainliest
Answer:
4.5V
Explanation:
Potential Difference (PD) = 9v
Let R1 = 2ohm, R2 = 3ohm and R3 = 6ohm
Now equivalent resistance in the circuit = 2 + (1/3 + 1/6) ohm
= 2 + 1/2 ohm
= 2 + 2/1 ohm ( Reason : as the 3ohm and 6ohm resistors were in parallel combination )
= 4 ohm
Now, by Ohm's law, we have
V = IR
=> 9 = I×4
=> 2.25A = I
Now, the voltage across the 2ohm resistor = (2.25 × 2)V = 4.5V Ans.
(The math was fully soved by me and is completely verified. Hope it was helpful.)