Question

please and both pls...... it's very urgent ​

Answer 1

Step-by-step explanation:

2nd question is not clear enough

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Answer 2

Answer:

1. ∠x = ∠y = ∠z = 40°

2. xy

Step-by-step explanation:

1. Given,

ABCD is a parallelogram.

AB is parallel to CD,

(i.e) AB ll CD

similarly,

AD ll BC

∠ADC = 100°

∠BAC = 40°

∠BAC = ∠y = 40° ( alternate interior angles )

In Δ ADC,

∠ADC + ∠x + ∠y = 180° ( angle sum property of triangle )

100° + ∠x + 40° = 180°

140° + ∠x = 180°

∠x = 40°

∠DCB = ∠DCA + ∠BAC

          = ∠y + ∠z

∠DCB = 40° + ∠z

In parallelogram, sum of adjacent angles is 180°,

So, ∠DAC + ∠DCB = 180°

       100° + 40° + ∠z = 180°

       140° + ∠z = 180°

      ∠z = 40°

Therefore, ∠x = ∠y = ∠z = 40°

2.  a x b x a^2   m^4 xy

    ________ x ______

  m x m x m^2     a^3 b

= a^3 b x m^4 xy

  ____________

     m^4 x a^3 b

( In numerator and denominator, a^3 b x m^4 get cancelled )

= xy

Therefore,

a x b x a^2     m^4 x y

________  x  ______ = xy

m x m x m^2    a^3 b