please and this . understanding quadrilateral
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Hey there!
★ We are given,
Angle BOC is 56°
★ To find: Angle ADO
★ Construction: Let E be the Mid point of Side AD
★ Proof:
Since, Diagonals of a rectangle (Given) are Equal & bisect each other.
So, OA = OB = OC = OD -----(1)
Tn the triangles OED and OEA
OA = OD (by eq. 1)
OE = OE (Common)
AE = ED (by Construction)
Therefore,
Triangle OED ≅ Triangle OEA
Now,
Angle AOD = Angle BOC = 56° (Vertically opposite angles)
Anghle AEO = 90° (By construction)
Angle AOE = DOE = 28° [Half of anlgle 56°]
In AEO by angle sum prop. of triangle
Angle DAO = 62°
Now, our final step
In triangle DAO
by angle sum prop. of triangle
Angle AOD + Angle DAO + Angle ADO = 180°
62° + 56° + Angle ADO = 180°
Angle ADO = 62°
HOPE IT HELPED ^_^
#EshanSingh1
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★ We are given,
Angle BOC is 56°
★ To find: Angle ADO
★ Construction: Let E be the Mid point of Side AD
★ Proof:
Since, Diagonals of a rectangle (Given) are Equal & bisect each other.
So, OA = OB = OC = OD -----(1)
Tn the triangles OED and OEA
OA = OD (by eq. 1)
OE = OE (Common)
AE = ED (by Construction)
Therefore,
Triangle OED ≅ Triangle OEA
Now,
Angle AOD = Angle BOC = 56° (Vertically opposite angles)
Anghle AEO = 90° (By construction)
Angle AOE = DOE = 28° [Half of anlgle 56°]
In AEO by angle sum prop. of triangle
Angle DAO = 62°
Now, our final step
In triangle DAO
by angle sum prop. of triangle
Angle AOD + Angle DAO + Angle ADO = 180°
62° + 56° + Angle ADO = 180°
Angle ADO = 62°
HOPE IT HELPED ^_^
#EshanSingh1
#Follow me
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