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2)
Since p ll q
and l ll m
angle B = 90
angle D.= 90
since, angles at the same side of transversal are supplemantary
Therefore, angle A = 90
angle C = 90
since all the angles are 90 therefore ABCD is a rectangle.
3)
(i) angle DAB = angle ABP = 40
Since alternate interior angles are equal
Therefore lines are ll
BP ll AD - (1)
(ii)angle QCD = angle CDA = 90
Since alternate interior angles are equal
Therefore lines are ll
CQ ll AD -(2)
(iii) From (1) & (2)
BP ll AD ll CQ
Therefore BP ll CQ
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