Question

please ans as fast as possible​

Answer 1

Answer:

0<x<1

Step-by-step explanation:

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Answer 2

Answer:

let us.solve the determinant

cosx(cosx*0 - (-sin(x+y)*1) - (-sinx)(sinx*0 - cos(x+y)) + 1(-sinxsin(x+y) - cosx cos(x+y))

= cosx sin(x+y) - sinx cos(x+y) - (cosx cos(x+y) + sinx sin(x+y)

= sin(x+y - x) - cos(x+y - x)

= siny - cosy

let

f(y) = siny - cosy

f'(y) = cosy + siny

for f(y) to be maximum or minimum

f'(y) = 0

cosy + siny = 0

siny = - cosy

siny/cosy = -1

tany = -1 = tan(-π/4)

y= -π/4

siny - cosy

= sin(-π/4) - cos(-π/4)

= -1/√2 - 1/√2

= -2/√2

= -√2

clearly this is the minimum value that siny - cosy can have for a particular y

similarly the maximum value can be √2

so the interval would be [-√2,√2]