Question

please ans. correctly with detail solution.

a drunked man walks 3 steps forward and 2 step backward. a distance between him and well is 11m. 1 step = 1 m. how many steps drunked man take to fall in the well?
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Answer 1

Answer:

Explanation:The man would be moving in the following fashion, where the final answer to each line below is the effective number of metres he has moved towards the pit:

(Remember that each line consists of the man moving 5 steps forward then 3 steps backward, so a total of 5+3 = 8 steps)

0+5–3 = 5–3 = 2

2+5–3 = 7–3 = 4

4+5–3 = 9–3 = 6

6+5–3= 11–3 = 8

8+5–3 = 13 - 3 = 10

At this point, we stop because before he moves backward 3 steps in this last line, he has already reached 13 i.e. he has already fallen into the pit.

We know that the man has already walked 4 * 8 = 32 steps at the end of the 4th line. In the 5th line, he only walks the 5 steps forward.

So, total number of steps walked = 32 + 5 = 37