Math, asked by urvashisharma123, 8 months ago

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Answered by deepsen640
2

Step-by-step explanation:

Total numbers of elementary events are: 10 x 9= 90

Being numbers are of non-replacing nature and order matters

Let E be the event of a/b as an integer

Favorable events are:

2/1, 3/1 , 4/1, 4/2, 5/1 , 6/1, 6/2 , 6/3 , 7/1 , 8/4 , 8/2 , 8/1, 9/3 , 9/1 , 10/5 , 10/2 , 10/1

Numbers of favorable outcomes are: 17/90.

Answered by Siddharta7
0

Answer:

17/90

Step-by-step explanation:

Given, two numbers are selected without replacement from integers 1 to 10.

Let E be the event of a/b as an integer,

Favorable events are:

2/1, 3/1 , 4/1, 4/2, 5/1 , 6/1, 6/2 , 6/3 , 7/1 , 8/4 , 8/2 , 8/1, 9/3 , 9/1 , 10/5 , 10/2 , 10/1.

Thus, favorable number of cases  = 17.

Total cases are,

(1/2, 1/3, ... 1/10), (2/1, 2/3, .... 2/10), ..... (10/1, 10/2, 10/3, ..... 10/9)

So,

Total number of cases = 9 * 10 = 90

Therefore,

Required probability = 17/90.

Hope it helps!

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