Question

PLEASE ANS IN BRIEF and first correct answer I will give brainlist​

Answer 1

Answer:

cos theata=12/13

marks as brainliest

Answer 2

Answer:

$(c)\frac{12}{13}$

Step-by-step explanation:

Consider Triangle BDC, BC is the hypotenuse

BD = 4 & DC = 3

By Pythagoras theorem,

$=>BC^{2} =DC^2+BD^2$

$=>BC^2=3^2+4^2$

$=>BC=\sqrt{9+16} =\sqrt{25}=5$ ------ 1

Now, consider Triangle ABC, AC is the hypotenuse

AB = 12 & BC = 5 (From 1)

From Pythagoras theorem,

$=>AC^2=AB^2+BC^2$

$=>AC=\sqrt{12^2+5^2}$

$=>AC=\sqrt{144+25}=\sqrt{169} =13$

So, we know that

$=>Cosx=\frac{adjacent}{hypotenuse}$

$=>Cosx=\frac{12}{13}$

Hope that you've understood the solution.