Physics, asked by aishwaryapi2007, 5 hours ago

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Answered by SwarajBose
1

Answer:

Explanation:

a. Line OA & BC = Uniformly accelerated motion

Line OA is with Positive Acceleration & Line BC is with negative Acceleration

b. Decrease in Velocity = 120 - 0 = 120 m/s, time taken = 10 - 6 = 4 Sec

Acceleration = -\frac{120}{4} = -30m/s^2

c. At AB part the object observes constant velocity

d. Change in velocity = 120 m/s, time taken 3 sec

Acceleration = \frac{120}{3} = 40m/s^2

Force=Mass\times Acceleration = \frac{50}{1000}\times40$ Newton $= \frac{2000}{1000}$ Newton $ = 2$ Newton$

e.

Force=Mass\times Acceleration = \frac{50}{1000}\times30$ Newton $= \frac{1500}{1000}$ Newton $ = 1.5$ Newton$

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