Question

please ans it asap its v important and ill surely mark as brainliest​

Answer 1

Hope this will help u

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Answer 2

hey mate

here is your answer...

Answer:

the molar mass of Na2CO3 is 106 g.(46+12+48)

thus,

the number of moles in 58 g of Na2CO3=1/2

thus , number of Na2CO3 molecules=1/2*6.022*10^23

=>3.011*10^23

thus,

No of Na atoms in 58 g of Na2CO3=2*3.011*10^23

=6.022*10^23

No of C atoms in 58 g of Na2CO3=1*3.011*10^23

=3.011*10^23

No of O atoms in 58 g of Na2CO3=3*3.011*10^23

=9.033*10^23