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5
sin square theta plus cos square theta is equal to 1
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dear pls explain it .. on the 2nf step plsss
just split 7sin2b into 4 sin square and 3 sin square and take three common and then put the value of sin square theta and cos square theta as 1
aapne sin²B and Cos²B likhna saayad bhul gaye the 2nd and 2rd step me ryt
(sin²B+cos²B)......****
sin²B = 1/4 ke baad nahi samajh me aa raha ...aapne 1/2 kaise kar diya
maine dono side square root le liya
to sin square sin ban gaya aur 1/4 1/2 ban gaya
ooo
thanks bhai
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4
7sin² B + 3 cos²B = 4( sin²B+ cos²B)
4sin² B + 3sin² B + 3 cos²B = 4( sin²B+ cos²B)
4sin² B + 3 = 4 {reason: sin²B + cos²B = 1}
4sin²B = 1
sin² B = 1/4
now:
sin²B + cos²B = 1
1/4 + cos²B = 1
cos²B = 1 - 1/4 = 3/4
therefore:
cot²B = cos²B/sin²B
cot²B = (3/4)/ (1/4)
cot²B = 3
therefore, cotB = √3
Brother ek doubt hai
bol bhai
Bhai apne ans. me comment check kar
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