Question

Please ans It Fast..Question from Cicle..Explain NicelY

Answer 1

Answer:

35 °

Step-by-step explanation:

∠AOC= 180° - ∠AOB

          =180° - 70° = 110°

Now, OA and OC both are the radii of the circle.

∴ OA = OC

Hence, an isosceles triangle ΔAOC is formed where OA = OC

∴ ∠OAC = ∠OCA = (180° - ∠AOC) / 2 = (180° - 110°) / 2 = 70°/2 = 35°

----------------Hope you like it ;-)------------

Answer 2

Hello mate !!!!!!

Here is your answer......

In this figure arc AB subtend a angle on center and on the remaining part of the circle .

We know that angle subtende by a arc at center is double of angle subtended on remaining circle

ATQ

2<ACO = < AOB

<ACO = 70/2 = 35°

Since BOC is a straight line,

<COA + < AOB = 180°

< COA = 180 - < AOB

< COA = 180° - 70°

< COA = 110°

In triangle AOC

< COA + < AOC + < OAC = 180°

110° + 35° +< OAC = 180°

< OAC = 180° - 145°

< OAC = 35°

HOPE THIS WILL HELP YOU.....