Question

please ans me guys






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Answer 1

<Q = 60

tan 60= PT/QT IN PQT

PT = tan 60 QT = √3 QT

QT = 1/2 QR

√3/2 QR = PT

now in PST

PS^2 = PT^2 + ST^2

QS + ST = QR/2

ST = QR/2 - QR/3

= 3QR - 2QR)/6 = QR/6

PS^2 = 3/4 QR^2 + QR^2/36

= 27 QR^2 + QR^2)/36 = 28 QR^2/36 = 7/9 QR^2

As its equilateral triangle


So PQ = QR

So PS^2 = 7/9 PQ^2

9 PS^2 = 7 PQ^2