Question

please ans me.. whosoever will ans me I'll follow that person​

Answer 1

Answer:

423

............i told u the answer

Answer 2

Step-by-step explanation:

Since the number contains three digits, it has a hundreds place, a tens place and a ones place.

It is given that the right most digit is 0. Let the digits in the hundreds place and tens place be x and y respectively. Thus, the number is  

100x+10y+0=100x+10y.

It is also given that if the digits in the hundreds place and tens place are interchanged, the difference between the original number and the new number after interchange is 180.

=>100x+10y−(100y+10x)=180

=>100x+10y−100y−10x=180

=>90x−90y=180

=>90(x−y)=180

=>x−y=2                                            ......(i)

It is also given that if the digit in the hundreds place is halved and digits in tens place and ones place are interchanged, the difference between the original number and the new number after interchange is 180.  

=>100x+10y−(100x/2+0+y)=454

=>100x+10y−50x−y=454

=>50x+9y=464                                .....(ii)

Multiplying both sides of Eqn (i) by 50, we get

50x−50y=100

Eqn(i)−Eqn(ii)=>(50x−50y)−(50x+9y)=100−454

=>50x−50y−50x−9y=−354

=>−59y=−354

=>y=6

Now, substitute the value of y in the equation  x−y=2.  

=>x−6=2

=>x=8

Therefore, the three digit number xy0=860.

___________________________________________________________

- here are the steps!