Math, asked by shraddha33333333, 4 months ago

Please ans my question..​

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Answered by StormEyes
3

\sf \Large Solution!!

\sf \lim_{x\to 1}[\frac{x-2}{x^{2}-x}-\frac{1}{x^{3}-3x^{2}+2x}]

\sf \lim_{x\to 1}[\frac{x-2}{x(x-1)}-\frac{1}{x(x^{2}-3x+2)}]

\sf \lim_{x\to 1}[\frac{x-2}{x(x-1)}-\frac{1}{x(x^{2}-2x-x+2)}]

\sf \lim_{x\to 1}[\frac{x-2}{x(x-1)}-\frac{1}{x(x-2)(x-1)}]

\sf \lim_{x\to 1}[\frac{(x-2)^{2}-1}{x(x-2)(x-1)}]

\sf \lim_{x\to 1}[\frac{(x-2+1)(x-2-1)}{x(x-2)(x-1)}]

\sf \lim_{x\to 1}[\frac{\cancel{(x-1)}(x-3)}{x(x-2)\cancel{(x-1)}}]

\sf \lim_{x\to 1}\frac{x-3}{x(x-2)}

\sf \to \frac{1-3}{1(1-2)}

\sf \to \frac{\cancel -2}{\cancel -1}

\sf \to 2


chauhanaaditya235: thanks kar Doo pls Sara answers........
shraddha33333333: ok
chauhanaaditya235: thanks thanks thanks thanks thanks thanks thanks
shraddha33333333: wlcm
StormEyes: Welcome :)
shraddha33333333: thank you so much
shraddha33333333: on that day I was busy with work so I can't thank you
shraddha33333333: but you helped me
shraddha33333333: so thank you so much
StormEyes: Wlcm :D
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