Question

please ans my question :( = :)​

Answer 1

Step-by-step explanation:

From the above expression

−1≤

x

2

+x+1

≤1 and x(x+1)≥0

⇒0≤x

2

+x+1≤1andx

2

+x+1≥1

⇒x

2

+x+1=1

⇒x

2

+x=0

⇒x(x+1)=0

Hence there will be two solutions. One at x=−1 and another atx=0.

Answer 2

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