Question

please ans please guys​

Answer 1

Answer:

what is this about the question

Answer 2

$\mathsf \red{ { {1}^{st} \: question \: : \: \: \: \: \: \: (y + 3)}^{2} \: } \\ \\ \boxed{ \mathsf \blue{ {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} }} \\ \\ \mathsf{ {(y + 3)}^{2} \: = \: {y}^{2} + 6y + 9}$

$\mathsf \red{ {2}^{nd} question \: : \: \: {(d - g)}^{2} } \\ \\ \boxed{ \mathsf \blue{ {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} }} \\ \\ \mathsf{ {(d - g)}^{2} \: = \: {d}^{2} - 2dg + {g}^{2} }$

$\mathsf \red{ {3}^{rd} \: question \: : \: \: \: \: \: (x + y).(x - y)} \\ \\ \boxed{\mathsf \blue{(a + b).(a - b) = {a}^{2} - {b}^{2} }} \\ \\ \mathsf{(x + y).(x - y) \: = \: {x }^{2} - {y}^{2} }$

$\mathsf \red{ {4}^{th} \: question : \: \: \: {(y + 4)}^{3} } \\ \\ \boxed{ \mathsf \blue{ {(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3} } } \\ \\ \mathsf{{(y + 4)}^{3} \: = \: {y}^{3} + 12 {y}^{2} + 48y + 64}$

$\mathsf \red{ {5}^{th} \: \: questiom : \: \: {(x - 5)}^{3} } \\ \\ \boxed{\mathsf \blue{ {(a - b)}^{3} = {a}^{3} - 3 {a}^{2} b + 3a {b}^{2} - {b}^{3} }} \\ \\ \mathsf{{(x - 5)}^{3} \: = \: {x}^{3} - 15 {x}^{2} + 75x - 125}$

$\mathsf \red{ {6}^{th} \: \: question : \: \: \: (x + 3).(x + 5 )} \\ \\ \boxed{ \mathsf \blue{(x + a).(x + b) = {x}^{2} + (a + b)x + ab}} \\ \\ \mathsf{(x + 3).(x + 5 ) \: = \: {x}^{2} + 8x + 15 }$

$\mathsf\red{ {7}^{th} \: \: \: question : \: {(2c + d - 3b)}^{2} } \\ \\ \boxed{ \mathsf \blue{ {(a + b - c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab - 2bc - 2ca }} \\ \\ \mathsf{ {(2c + d - 3b)}^{2} \: = \: 4 {c}^{2} + {d}^{2} + 9 {b}^{2} + 4cd - 6bd - 12bc }$

$\mathsf{}$

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