Question

please ans ques no. 38 by solving it properly

Answer 1

This is ur ans hope it will help you in case of any doubt comment below

Answer 2

there are three resistors in connection.
two are in parallel so formula used will be,
$r = \frac{x \times y}{x + y}$
so total resistance for paralle will be
$\frac{6 \times 6}{6 + 6} = \frac{36}{12} = > r = 3$

now one is connected in series with the parallel connection, so
$tr = r + rs \\ tr = 3 + 6 \\ tr = 9 \: ohm$