please ans question no. 9
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u=126 km/hr = 35 m/s
v=54 km/hr = 15 m/s
s =500 m
by third equation of motion
2as= v2-u2
2×500×a = 15×15-35×35
a= -1000/1000
a = -1m/s²
case 2
v =u +at
0= 15-1t
t =15 second
therefore train will stop after 15 seconds.
2×-1×s= 0²-15²
-2s= -225
s= 112.5m
therefore the train will stop after travelling 112.5 m
v=54 km/hr = 15 m/s
s =500 m
by third equation of motion
2as= v2-u2
2×500×a = 15×15-35×35
a= -1000/1000
a = -1m/s²
case 2
v =u +at
0= 15-1t
t =15 second
therefore train will stop after 15 seconds.
2×-1×s= 0²-15²
-2s= -225
s= 112.5m
therefore the train will stop after travelling 112.5 m
vallabhk123:
hey thank u !
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