please ans the question no32
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p^2-q^2=(p+q)(p-q)
=( tan + sin + tan - sin )(tan + sin - tan + sin)
=(2 tan)(2 sin)
= 4 tan sin
adarsh8472:
but how
evaluate 4√pq
it is equal to 4 tantheta sin theta
got it
it would be 4√tan^2 - sin2 bro.
take sin^2 common
and solve
i can't understand
please send img of the ans that u have solved
I can't understand
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