Math, asked by adarsh8472, 1 year ago

please ans the question no32

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Answered by yajmera8

1

p^2-q^2=(p+q)(p-q)

=( tan + sin + tan - sin )(tan + sin - tan + sin)

=(2 tan)(2 sin)

= 4 tan sin

adarsh8472: but how

ayush000163: evaluate 4√pq

ayush000163: it is equal to 4 tantheta sin theta

ayush000163: got it

yajmera8: it would be 4√tan^2 - sin2 bro.

ayush000163: take sin^2 common

ayush000163: and solve

adarsh8472: i can't understand

adarsh8472: please send img of the ans that u have solved

adarsh8472: I can't understand

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