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HEY mate here is your answer.
SECTION-B
5)4^n can never end with 0 .
to end with the digit 0 the number must have two factors that is 2 and 5 in the form of 2^x5^y. But in 4^n it has only 2 as a factor. Hence it can never be end with 0.
6) Solution in the pic.
Hope it helps you.
^_^
SECTION-B
5)4^n can never end with 0 .
to end with the digit 0 the number must have two factors that is 2 and 5 in the form of 2^x5^y. But in 4^n it has only 2 as a factor. Hence it can never be end with 0.
6) Solution in the pic.
Hope it helps you.
^_^
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