Question

Please ans the this question in the attachment

Answer 1

Answer:

don't know...

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Answer 2

Answer:

Here is you answer:

Given:

∠ADC≅∠AEB

BE=DC ----------(2)

Now, In triangle ΔDFB and ΔEFC,

∠DFB=∠EFC.     (vertically opposite angle theorem)

And, BE=DC.     (Given)

And ∠A=∠A       (Common)

Thus, ΔABE≅ΔAEC. [AAS Congruency]

Subtract quadrilateral □ADFE on both sides.

ΔABE-□ADFE≅ΔAEC-□ADFE

ΔDFB≅ΔEFC.

By C.P.C.T, [Corresponding parts of congruent triangles are equal]

BF=FC ------------(1)

Subtract (1) and (2)

You will get:

BE-BF=DC-FC

⇒DF=EF.

HOPE THIS HELPS :D