Question

please ans this ....

Answer 1

Answer:

1.2 m

Explanation:

$\nu = \frac{\sqrt{ T} }{2l\sqrt{ \mu } }$

where T is tension and μ is the linear density of the wire.

Tension, T = mg ie, T ∝ m

ie, $\nu \ \alpha\ \frac{\sqrt{m} }{l}$ , where l is the length.

Since both wires have same fundamental frequency,

ν₁ = ν₂

$\frac{\sqrt{1.5} }{60} = \frac{\sqrt{6} }{y} \\\\y = \frac{60\sqrt{6} }{\sqrt{1.5} } \\\\y = 2 * 60\\ = 120 cm\\ = 1.2m$