Math, asked by akshay180, 1 year ago

please ans this ...........................

Attachments:

sivaprasath: side = 25m, length to fence is permiter, p=4a=4(25)=100m
sivaprasath: 4 tmes= 4(100)=400m
akshay180: tqs

Answers

Answered by Bunti360
2
Here is the Solution :

Given that,
ABCD is a Square of Area 625cm²,

We need to find length of wire required to fence,

So basically we need to find Perimeter,

We know that,
All sides of a square are of equal length,

Perimeter of General square = 4*Side of square

Area of a general square = Side ²,

Let us assume side be a,

According to the Question,
a² = 625 cm²,
=> Applying root on both sides,
=> a = +25 or -25 cm, But length can't be -ve,

So a = +25 cm = Length of 1 side of fence,

Length of wire required to fence = 4*25cm = 100cm [Because we have to calculate Perimeter]

Length required to fence 4 times = 4*100 = 400 cm

Therefore the answer is 400 cm,

Hope you understand, Have a great day !
Thanking you, Bunti 360 !!

Bunti360: Thank you for choosing this answer as the brainliest answer !.
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