please ans this ...........................
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sivaprasath:
side = 25m, length to fence is permiter, p=4a=4(25)=100m
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Here is the Solution :
Given that,
ABCD is a Square of Area 625cm²,
We need to find length of wire required to fence,
So basically we need to find Perimeter,
We know that,
All sides of a square are of equal length,
Perimeter of General square = 4*Side of square
Area of a general square = Side ²,
Let us assume side be a,
According to the Question,
a² = 625 cm²,
=> Applying root on both sides,
=> a = +25 or -25 cm, But length can't be -ve,
So a = +25 cm = Length of 1 side of fence,
Length of wire required to fence = 4*25cm = 100cm [Because we have to calculate Perimeter]
Length required to fence 4 times = 4*100 = 400 cm
Therefore the answer is 400 cm,
Hope you understand, Have a great day !
Thanking you, Bunti 360 !!
Given that,
ABCD is a Square of Area 625cm²,
We need to find length of wire required to fence,
So basically we need to find Perimeter,
We know that,
All sides of a square are of equal length,
Perimeter of General square = 4*Side of square
Area of a general square = Side ²,
Let us assume side be a,
According to the Question,
a² = 625 cm²,
=> Applying root on both sides,
=> a = +25 or -25 cm, But length can't be -ve,
So a = +25 cm = Length of 1 side of fence,
Length of wire required to fence = 4*25cm = 100cm [Because we have to calculate Perimeter]
Length required to fence 4 times = 4*100 = 400 cm
Therefore the answer is 400 cm,
Hope you understand, Have a great day !
Thanking you, Bunti 360 !!
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