Question

please ans this first ans will be brainlist ​

Answer 1

$\mathfrak{\large{\underline{\underline{Given:-}}}}$

The radius of circular track is 200 m

$\mathfrak{\large{\underline{\underline{To find:-}}}}$

1) The distance and displacement in half round.

2) The distance and displacement in one complete round.

$\mathfrak{\large{\underline{\underline{Answer:-}}}}$

In half round the distance cover is equal to :-

The circumference of semicircle :-

Circumference of semicircle = πr

$\implies$ $\bold{</strong><strong>S</strong><strong> </strong><strong>=</strong><strong> </strong><strong>}</strong><strong> \frac{314}{100} \times 200</strong><strong>$

$\implies$ $\bold{S = 628 m}$

The displacement is equal to the diameter of circle = 2r

$\implies$ $\bold{</strong><strong>S</strong><strong> </strong><strong>=</strong><strong> </strong><strong>2</strong><strong> </strong><strong>×</strong><strong> </strong><strong>2</strong><strong>0</strong><strong>0</strong><strong>}$

$\implies$ $\bold{</strong><strong>S</strong><strong> </strong><strong>=</strong><strong> </strong><strong>4</strong><strong>0</strong><strong>0</strong><strong> </strong><strong>m</strong><strong> }$

2) In one complete round the distance cover is equal to the circumference of circle.

Circumference of circle = 2πr

$\implies$ $\bold{</strong><strong>S</strong><strong> </strong><strong>=</strong><strong> </strong><strong>2</strong><strong> </strong><strong>×</strong><strong> </strong><strong>\frac{314}{100} \times 200</strong><strong>}</strong><strong>$

$\implies$ $\bold{</strong><strong>S</strong><strong> </strong><strong>=</strong><strong> </strong><strong>2</strong><strong> </strong><strong>×</strong><strong> </strong><strong>6</strong><strong>2</strong><strong>8</strong><strong> </strong><strong> }$

$\implies$ $\bold{</strong><strong>S</strong><strong> </strong><strong>=</strong><strong> </strong><strong>1</strong><strong>2</strong><strong>5</strong><strong>6</strong><strong> </strong><strong>m</strong><strong>}$

The displacement travelled by a body will be 0 because the body remains come to its original position.

Answer 2

Hey mate here is your answer

⭐Given Radius of the circular track =200m

⭐To Find- 1) Distance and displacement of half round

2) Distance and displacement of One complete round

⭐Solution :-1) # In half round the distance covered by the athlete is equal to the circumference of semicircle

i.e C =πr

S=3.14 ×200 ( C=S, because half the circumference is the distance travelled by the athlete)

S=314 ×200

100

S= 628m .

#Displacement completed in half round is equal to the diameter of the circle

i.e S=2r

S=2×200

Displacement ,S=400m.

2)#In 1 complete round the distance travelled by the athlete is equal to the circumference of the circle

i.e C=2πr

S=2×3.14×200 ( where C=S, because circumference of the circle is equal to the distance covered in 1complete round )

S=2×314 ×200

100

S=4×314

S=1256.

#Displacement covered in 1 complete round is 0 m because the athlete has came back to its initial point and we know that displacement is the shortest distance between the initial and final position and here the displacement between initial and final position is 0m.

Hope it helps

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