Math, asked by suman0766, 7 months ago

please ans. this ques. ​

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Answered by viperisbackagain
0

Step-by-step explanation:

a) by simplification

 \frac{3}{4} (7y - 1) - (2y - ( \frac{1 - y}{2} ) = y +  \frac{3}{2}

 \frac{21y}{4}  -  \frac{3}{4}  -   \frac{4y - 1 + y}{2}  =  \frac{2y + 3}{2}

 \frac{21y - 3 - 8y - 2 + 2y}{4}   =  \frac{2y + 3}{2}

 \frac{16y - 5}{4}  =  \frac{2y + 3}{2}

By cross multiplication

2(16y - 5) = 4(2y + 3)

32y - 10 = 8y + 12

32y - 8y = 12 + 10

24y = 22

so

y =  \frac{22}{24}

y =  \frac{11}{12}

b)

3y + 2 = 4(7y + 3)

3y + 2 = 28y + 12

3y - 28y = 12 - 2

 - 25y = 10

y =  \frac{10}{ - 25}

y =  -  \frac{2}{5}

hope it helps

be brainly

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