Question

please ans this question ​

Answer 1

Answer:

If 3x + 4y = 18 and 4x + 3y = 17, then x =2 and y = 3

Step-by-step explanation:

Given

3x+4y=18

$x=\frac{18-4y}{3}$

4x+ 3y = 17

$4(\frac{18-4y}{3} )+3y =17\\\\\frac{ 72-16y }{3} +3y = 17\\\\\frac{72-16y+9y}{3} =17\\\\72-7y = 17*3\\\\72-7y= 51\\\\7y = 72-51\\\\7y=21\\\\y=21/7\\\\y=3$

y= 3

$x=\frac{18-4y}{3}$

= (18-12)/3

=6/3

= 2

So x= 2, y= 3

Answer 2

Answer:

The solution to the simultaneous equations is: x=2  ,y=3.

Step-by-step explanation:

We have two simultaneous equations in terms of x and y, first we need to make either x or y equal in both the equations by multiplying suitable constants to the equations. Then we solve both the equations simultaneously to find the value of the other variable and then substitute the value of this variable in one of the original equations.

3x+4y=18  (i)x4

4x+3y=17   (ii)x3

12x+16y=72  (iii)

12x+9y=51    (iv)

Solving (iii) and (iv) we have,

16y-9y=72-51

7y=21

y=3

Substituting y=3 in equation (i)

3x+(4x3)=18

3x+12=18

3x=6

x=2

Therefore, x=2,y=3