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since x= 2/3 and x = -3 are the roots of the quadratic equation ;
a x^2 + 7x + b = 0
a[2/3 ]^2 + 7[2/3 ] + b = 0
4a + 42 + 9 b = 0
4 + 9 b = -42.........(1)
a( - 3 )^2 + 7( - 3 ) + b = 0
9a - 21 + b = 0
9a + b = 21............(2)
some equations first and second we obtain ...
81a + 9b = 189
4a + 9b = -42
on subtracting above two equations we get ....
77a = 231
a = 3
now from equation two we get ...
9( 3 ) + b = 21
b = - 6
hence the values of A and B are 3 and - 6 respectively
THANKS________
^_^^_^^_^
________________
since x= 2/3 and x = -3 are the roots of the quadratic equation ;
a x^2 + 7x + b = 0
a[2/3 ]^2 + 7[2/3 ] + b = 0
4a + 42 + 9 b = 0
4 + 9 b = -42.........(1)
a( - 3 )^2 + 7( - 3 ) + b = 0
9a - 21 + b = 0
9a + b = 21............(2)
some equations first and second we obtain ...
81a + 9b = 189
4a + 9b = -42
on subtracting above two equations we get ....
77a = 231
a = 3
now from equation two we get ...
9( 3 ) + b = 21
b = - 6
hence the values of A and B are 3 and - 6 respectively
THANKS________
^_^^_^^_^
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