Question

please ans this question​

Answer 1

sum of the exterior angle of a triangle is 180

therefore angle ACD +angleBAE +angleCBF =180

Answer 2

∠abc+∠bac+∠acb=180(angle sum property) ------1 e

∠abc+∠cbf=180(linear pair)

∠abc=180-∠cbf

similarly,

∠bac=180-∠bae

∠acb=180-∠acd

now substituting these values in the first eqn

180-∠cbf+180-∠bae+180-∠acd=180

180+180+180-∠cbf-∠bae-∠acd=180

180+180+180-180=∠cbf+∠bae+∠acd

∠cbf+∠bae+∠acd=180+180

∠cbf+∠bae+∠acd=360

hence proved

plzz mark me the brainliest