Question

please ans this question correctly.​

Answer 1

Given:-

•Volume of the cube=729m³

To find:-

•Surface area of the cube

Solution:-

We know that volume of a cube----

$= > ({side})^{3}$

$= > ( {side})^{3} = 729$

$= > side = \sqrt{729}$

$= > side = 9m$

Thus,side of the cube is 9m.

Now,we know that Total Surface Area of a cube is----

$= > 6 {a}^{2}$

Where 'a' is side of the cube

=>6(9)²

=>81×6

=>486m²

Thus,surface area of the cube is 486m².

Answer 2

Step-by-step explanation:

Volume of the cube=729m³

To find:-

•Surface area of the cube

Solution:-

We know that volume of a cube----

= > ({side})^{3}=>(side)

3

= > ( {side})^{3} = 729=>(side)

3

=729

= > side = \sqrt{729}=>side=

729

= > side = 9m=>side=9m

Thus,side of the cube is 9m.

Now,we know that Total Surface Area of a cube is----

= > 6 {a}^{2}=>6a

2

Where 'a' is side of the cube

=>6(9)²

=>81×6

=>486m²

Thus,surface area of the cube is 486m².