.please ans this question if anyone
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tan² θ-sin² θ=(sin² θ/cos² θ)-sin² θ
=[sin² θ-(sin² θ cos² θ)]/cos² θ
=[sin² θ(1-cos² θ)]/cos² θ
=(sin² θ/cos² θ)×sin² θ [∵1-cos² θ=sin² θ]
=tan² θsin² θ
Hope it helps u :-)
=[sin² θ-(sin² θ cos² θ)]/cos² θ
=[sin² θ(1-cos² θ)]/cos² θ
=(sin² θ/cos² θ)×sin² θ [∵1-cos² θ=sin² θ]
=tan² θsin² θ
Hope it helps u :-)
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