Math, asked by princejimit, 1 year ago

.please ans this question if anyone

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Answered by lekhahasa
1
tan² θ-sin² θ=(sin² θ/cos² θ)-sin² θ
                   =[sin² θ-(sin² θ cos² θ)]/cos² θ
                   =[sin² θ(1-cos² θ)]/cos² θ
                   =(sin² θ/cos² θ)×sin² θ              [∵1-cos² θ=sin² θ]
                   =tan² θsin² θ
Hope it helps u :-)
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