please ans this question immediately
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Equivalent weight of an element is the weight of element which will combine with 8g of oxygen.
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Weight of element = W1 g
weight of its oxide = W2 g
weight of oxygen used to combine with W1 g of the element = (W2 - W1)g
So (W2 - W1)g of oxygen combines with W1 g of the element.
1g of oxygen will combine with = W1 / (W2 - W1) g of element
8g of oxygen will combine with = [W1 / (W2 - W1)] × 8 g of element.
So equivalent weight = [ W1 / (W2 - W1) ] × 8
Answer is C.
________________________
Weight of element = W1 g
weight of its oxide = W2 g
weight of oxygen used to combine with W1 g of the element = (W2 - W1)g
So (W2 - W1)g of oxygen combines with W1 g of the element.
1g of oxygen will combine with = W1 / (W2 - W1) g of element
8g of oxygen will combine with = [W1 / (W2 - W1)] × 8 g of element.
So equivalent weight = [ W1 / (W2 - W1) ] × 8
Answer is C.
TPS:
now equivalent weight of CaO by option C is: [40 / (56-40)] × 8 = 40/16 × 8 = 20
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option © is correct answer
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