Question

please ans this question. ques15

Answer 1

Let number on unit place be x
number on tens place be y.
Therefore digit = 10y+x
Now, According to question

x-y = 3 ------->(1)
Also,
7(10y+x) = 4(10x+y)
70y+7x = 40x+4y
70y-4y=40x-7x
66y=33x
2y=x ( divided by 33)--------->(2)
Putting value of equation (2) in equation (1) we get,
2y-y=3
y=3
now putting value of y in equation (2) we get ,
2(3)=x
x=6
therefore digit = 10y+x
= 10(3)+6
= 30+6 = 36
HOPE IT HELPS YOU
ALL THE BEST FOR EXAM..........