Math, asked by peeyushidhamma, 5 hours ago

please ans this very urgent!! ​

Attachments:

Answers

Answered by prpoojarajput
0

Answer 99

x^2 + y^2 = (√3-√2)^2 + (√3+√2)^2

x^2 + y^2 = (√3-√2)^2 + (√3+√2)^2 (√3+√2)^2 (√3-√2)^2

x^2 + y^2 = (√3-√2)^2 + (√3+√2)^2 (√3+√2)^2 (√3-√2)^2 = 3+2-2√6 + 3+2+2√6

x^2 + y^2 = (√3-√2)^2 + (√3+√2)^2 (√3+√2)^2 (√3-√2)^2 = 3+2-2√6 + 3+2+2√6 3+2+2√6 3+2 -2√6

x^2 + y^2 = (√3-√2)^2 + (√3+√2)^2 (√3+√2)^2 (√3-√2)^2 = 3+2-2√6 + 3+2+2√6 3+2+2√6 3+2 -2√6 = 5 - 2√6 + 5 + 2√6

x^2 + y^2 = (√3-√2)^2 + (√3+√2)^2 (√3+√2)^2 (√3-√2)^2 = 3+2-2√6 + 3+2+2√6 3+2+2√6 3+2 -2√6 = 5 - 2√6 + 5 + 2√6 5 + 2√6 5 - 2√6

x^2 + y^2 = (√3-√2)^2 + (√3+√2)^2 (√3+√2)^2 (√3-√2)^2 = 3+2-2√6 + 3+2+2√6 3+2+2√6 3+2 -2√6 = 5 - 2√6 + 5 + 2√6 5 + 2√6 5 - 2√6 = 25 +24 -20√6 +25 +24+20√6

= 98 + xy

= 99

( xy will be 1)

Similar questions