Question

please ans thus
$..$

Answer 1

there are first three answers last I don't know.

Answer 2

$8) {(97)}^{2} \\ ( {100 - 3)}^{2} \\ ( {100)}^{2} - 2 \times 100 \times 3 + {(3)}^{2} \\ 10000 - 600 + 9 \\ 9409$
$9)x = 2 \\ f(2) = 0 \\ k( {2)}^{2} - 2(2) - 1 = 0 \\ 4k - 4 - 1 = 0 \\ 4k = 5 \\ k = \frac{5}{4} \: \: ans$
$10) x + \frac{1}{x} = 6 \\ \\ ( {x + \frac{1}{x} )}^{2} = 36 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2 = 36 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 36 - 2 = 34 \\ ( { {x}^{2} + \frac{1}{ {x}^{2} }) }^{2} = ( {34) }^{2} \\ \\ {x}^{4} + \frac{1}{ {x}^{4} } + 2 = 1156 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 1156 - 2 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 1154 \: \: \: ans$
11)
$(3 \times 2 + 2 \times 1 - 3( - 1)) \\ 6 + 2 + 3 = 11 \\ 9 {x}^{2} + 4 {y}^{2} + 9 {z}^{2} - 6xy + 6yz + 9xz \\ 9 \times 4 + 4 \times 1 + 9 \times 1 - 6 \times 2 - 6 - 18 \\ 36 + 4 + 9 - 12 - 6 - 18 \\ 49 - 36 \\ 13 \\ = 11 \times 13 \\ = 143$