Question

please ans.
with solution​

Answer 1

Answer:

625 Meters

Explanation:

Given:

Initial velocity(u)=90 km/h or 25 m/s

Final velocity= 0 m/s (on rest)

Acceleration(a)= -0.5 m/s^2

Distance(s)=?

We know,

2as=v^2-u^2(Formula)

2(-0.5)s=0^2-25^2

-s=-625m

Or Distance(s)= 625m

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Answer 2

Solution :-

Putting all the value, we get

⇒ v = u2 + 2 as

⇒ (0)2= (25)2 + 2 ( - 0.5) s

⇒ s = 625 m

Hence, The train will cover a distance of 625 m before coming to rest.

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