Question

please anser me fast......

The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4 cm. What is the length of either of the remaining equal sides?

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Answer 1

Answer:

$a = \frac{11}{6} cm$

Step-by-step explanation:

Perimeter of an isosceles triangle = 2a + b

$5 = 2a + \frac{4}{3}$

$2a = 5 - \frac{4}{3}$

$2a = \frac{15 - 4}{3}$

$2a = \frac{11}{3}$

$a = \frac{11}{6} cm$