Question

please ansewer 42nd que ​

Answer 1

ANSWER⤵⤵

Now, the numbers between 101 and 999 which are divisible 10 are 110, 120, 130, .., 990.

Let this AP contains n terms.

Then, Hence, there are 89 numbers between 101 and 999 which are divisible by both 2 and 5.

Answer 2

Answer :

No divisible by 2 and 5 is 10

Form an AP of natural number present between 101 and 999

AP = 110, 120, 130,............, 990

From this AP series we get

a = 110

d = 10

nth term of the AP = 990

So

By the formula

$a+(n-1)d$

=> $a+(n-1)d=990$

=> $110+(n-1)10=990$

=> $(n-1)10=990-110$

=> $(n-1)= 880/10$

=> $n-1=88$

=> $n=88+1$

=> $n = 89$

Ans :- The natural number between 101 and 999 is 89