Please answer
1) Calculate the mass of Earth. Given, the force that Earth exerts on a
mass (m) of 1 kg at its surface is 9.8 N. The radius of Earth ( R ) is
6. 4 × 106 m.
2) Calculate the force of gravity between two students with mass 55 kg and
45 kg and they are 1 m away from each other.
3) If a small asteroid named ‘B612’ has a radius of only 20 m and mass of
1 × 104 kg, what is the acceleration due to gravity on its surface?
4) If the gravitational force between objects of equal mass is2. 3 × 10−8 N,
when the objects are 10 m apart, what is the mass of each object?
5) What is the gravitational force on a 70 kg object that is 6. 38 × 106 m
above the Earth’s surface?
6) Calculate the acceleration due to gravity at a point 1000 km above the
surface of Earth.
7) The force of gravity between 2 objects A and B is 100 N. When the mass
of B is doubled and the distance between them is quadrupled. What is
the new force?
8) A ball is thrown 60 m vertically into the air.
a) What was its initial velocity?
b) How much time does it take to reach the highest point?
9) A stone is dropped vertically downwards. What is the velocity of the
rock at 4 seconds? What is the displacement of the rock at 4 seconds?
10) A stone is allowed to fall from the top of a tower 50 m high and at the
same time another stone is projected vertically upwards from the
ground with a velocity of 20 m/s. Calculate when and where the two
stones will meet. (Assume g = 10 m s
2 ⁄ )
Answers
Answered by
1
Answer:
Given that,
Mass of the Earth m
1
=6×10
24
Kg
Mass of the Moon m
2
=7.4×10
22
kg
Distance between the Earth and the Moon d=3.84×10
5
km=3.84×10
8
m
Gravitational Constant G=6.7×10
−11
Nm
2
/kg
2
Now, by using Newton’s law of gravitation
F=
r
2
Gm
1
m
2
F=
(3.84×10
8
)
2
6.7×10
−11
×6×10
24
×7.4×10
22
F=
14.8225×10
16
297.48×10
35
F=20.069×10
19
F=20.1×10
19
N
Hence, the gravitational force of attraction is 20.1×10
19
N
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