Math, asked by athithya007, 4 months ago

please answer 1 st question in the attachment

Attachments:

Answers

Answered by madhavsanjulover
2

Answer:

I think 2 is the answer

b

Answered by Anonymous
10

\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\red{W}\green{E}\purple{R}}}

 \large(( \cos( \frac{\pi}{2} )  - x) +  \cos(\pi - x) )^{2}  + ( \sin( \frac{3\pi}{2} )  +  \sin(2\pi - x)){2}

 \large➟ ( \sin \: x +  \cos \: x)^{2}  + ( \cos \: x +  \sin \: x)^{2}

 \large➟( \cos \: x +  \sin \: x)^{2}  + (  - \sin \: x +  \cos \: x)^{2}

 \large➟  (\cos^{2} x+  \sin^{2} x) + 2 \cos x \sin  x +  (\sin^{2} x +  \cos^{2} x)- 2 \sin x \cos  x

 \large➟1 + 1

 \large➟ \: 2

\large\sf{\purple{ᴛʜᴇʀᴇғᴏʀᴇ \:  ᴛʜᴇ  \: ᴄᴏʀʀᴇᴄᴛ \:  ᴏᴘᴛɪᴏɴ  \: ɪs  \: 2) 2}}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

\large\bf{\underline{\pink{Hope \:  It \:  Helps  \: You!}}}

Similar questions