please answer 100 % correct
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hear is your answer
x=50
y=80
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Given, QT⏊TR,
∠TQR = 40°
∠QRT = x
∠QTR = 90°
∠PSQ = y => ∠PSR = 180° - y
In ∆QTR,
∠TQR + ∠QRT + ∠QTR = 180°
→ 40° + x + 90° = 180°
→ x + 130° = 180°
→ x = 180° - 130°
∴ x = 50°
NOW, In ∆PSR,
∠PSR + ∠PRS + ∠RPS = 180°
→ 180°-y + x + 30° = 180°
→ -y + 50° + 30° = 180° - 180°
→ 50° + 30° = y
→ y = 80°
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