Math, asked by amishi123a, 1 year ago

please answer??????????????????

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Answered by Divyankasc
5
p(x) = x² + x - 2
Instead of alpha and beta, I'll write a and b
So, p(x) = x² + x - 2
= x² + 2x - x - 2
= x(x + 2) -1(x +2)
= (x - 1)(x +2)
x = 1 ; x = (-2)

Therefore, a = 1, b = (-2)
1/a + 1/b = 1/1 + 1/2 = 3/2

OR, if a = -2 and b = 1
1/a + 1/b = -2 +1/2 = -3/2

Anonymous: huh
Anonymous: really but how
amishi123a: sorry minus3/2
Anonymous: aree LCM
Anonymous: liya h
Divyankasc: Correct!
Divyankasc: Corrected*
Divyankasc: :D
amishi123a: thanks
Divyankasc: Welcome:)
Answered by ItsBrainlyStarQueen
1

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\mathfrak{Answer\:is}

p(x) = x^{2} + x - 2

Instead \:of \:alpha \:and \:beta, \:I'll \:write \:a \:and \:b.

So, p(x) = x^{2} + x - 2

= x^{2} + 2x - x - 2

= x (x + 2) - 1 (x + 2)

= (x - 1) (x + 2)

x = 1 ; x = (-2)

Therefore, a = 1, b = (-2)

\frac{1}{a} + \frac{1}{b} = \frac{1}{1} + \frac{1}{2} = \frac{3}{2}

Or

If a = (-2) and \:b = 1

\frac{1}{a} + \frac{1}{b} = -2 + \frac{1}{2} = \frac{-3}{2}

\boxed{\boxed{Hope\:This\:Helps}}

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