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p(x) = x² + x - 2
Instead of alpha and beta, I'll write a and b
So, p(x) = x² + x - 2
= x² + 2x - x - 2
= x(x + 2) -1(x +2)
= (x - 1)(x +2)
x = 1 ; x = (-2)
Therefore, a = 1, b = (-2)
1/a + 1/b = 1/1 + 1/2 = 3/2
OR, if a = -2 and b = 1
1/a + 1/b = -2 +1/2 = -3/2
Instead of alpha and beta, I'll write a and b
So, p(x) = x² + x - 2
= x² + 2x - x - 2
= x(x + 2) -1(x +2)
= (x - 1)(x +2)
x = 1 ; x = (-2)
Therefore, a = 1, b = (-2)
1/a + 1/b = 1/1 + 1/2 = 3/2
OR, if a = -2 and b = 1
1/a + 1/b = -2 +1/2 = -3/2
Anonymous:
huh
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