Question

please answer ...............​

Answer 1

Pls write clearly
I am not able to see

Answer 2

Answer:

Prooved

Step-by-step explanation:

In the given fig.

CD ll EF, AB is a transversal.

AngleGPQ =Angle PQF (Alternate Interior)

GP and QH is a bisector.

Therefore, Angle CPG=GPQ, Angle PQH=HQF

Angle GPQ=PQH

Therefore, GPllQH

Hence, prooved

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