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Answer:
Prooved
Step-by-step explanation:
In the given fig.
CD ll EF, AB is a transversal.
AngleGPQ =Angle PQF (Alternate Interior)
GP and QH is a bisector.
Therefore, Angle CPG=GPQ, Angle PQH=HQF
Angle GPQ=PQH
Therefore, GPllQH
Hence, prooved
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