Math, asked by Aadhi002, 7 months ago

Please answer 125-8y^3

Answers

Answered by Anonymous
3

Answer:

(5-2y)(4y²+10y+25)

Step-by-step explanation:

125 - 8y³

(5)³ - (2y)³

(5-2y)(5²+ (2y)² + 5×2y) (since a³-b³=(a-b)(a²+b²+ab))

(5-2y)(25+4y²+10y)

(5-2y)(4y²+10y+25)

Answered by dorgan399
100

Step-by-step explanation:

\bold\blue{QUESTION}

FACTORISE 125-8y³

\bold\red{ANSWER}

125-8y³

=(5)³-(2y)³

=(5-2y)[5²+(2y)²+(5)(2y)].

{a³-b³=(a-b)(a²+b²+ab)}

SO ON FACTORISING,*125-8y³*

WE GET, (5-2y)[25+4y²+(10y)]

\bold\green{ADDITIONAL\: INFORMATION}

SOME IMPORTANT IDENTITIES

  • a²+b²+2ab=(a+b)²

  • a²+b²-2ab=(a-b)²

  • a²-b²=(a+b)(a-b)

  • a³+b³=(a+b)(a²+b²-ab)

  • a³-b³=(a-b)(a²+b²+ab)

  • a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

  • a³+b³+3ab(a+b)=(a+b)³

  • a³-b³-3ab(a-b)=(a-b)³
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