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your answer is d 80°
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In the given figure AE is // to OD,
and OC is the transversal 40°+angle EDO=180°( since,sum of two interior angles of same side of tranversal is 180°)
So,angle EDO = 180°-40°=140°
Now take the transversal as EB ,then
140°+angle CDE= 180°(since,sum of two interior angles of same side of the transversal is180°)
Therefore,angle CED=180-140=40°......
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