Question

Please answer 14 question? Total 3 cubes are joined not 2 cubes.

Class - 10th
Chapter - Surface area and Volume.

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Answer 1

Answer:

160 cm²

Step-by-step explanation:

The volume of cube = 64cm³

Side of cube 64/16=4cm

Length of resulting cuboid 4+4=8

Surface area

=2(lb+hl+bh)

=2(4(4)+4(8)+8(4)

=2(16+32+32)

=2(80)=160cm²

Hope it helps you

Answer 2

$\huge{\boxed {\mathbb {QUESTION}}}$

$3 \:cubes \:of\: volume\: 64{cm}^{3}\: are\: joined \\end \:to \:end. \:Find\: the\: length\: of\: the\: resulting\: figure$

$\huge{\boxed {\mathbb {ANSWER}}}$

${\boxed {\mathbb {GIVEN}}}$

• $Volume \:of\: a\: cube=64{cm}^{3}$

${\boxed {\mathbb {TO\:POVE}}}$

• $Total \:length(l)$

${\boxed {\mathbb {SOLUTION}}}$

$Let \:the\: sides\: of\: a\: cube\: be\: a$

$\implies {a}^{3}=64{cm}^{3}$

$\implies a=\sqrt[3]{64{cm}^{3}}$

$\implies{\boxed {\boxed {a=4cm}}}$

$Length$

$\implies a+a+a$

$Substitute\: the \:values$

$\implies 4+4+4$

$\implies {\boxed {\boxed {12cm}}}$

$\huge{\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

__________________________________________

$\huge{\boxed {\mathbb {EXTRA\:INFORMATION }}}$

• $Volume \:of\: cube=4{a}^{3}$
• $CSA\:of\:cube=4{a}^{2}$
• $TSA\:of\:cube=6{a}^{2}$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}$