please answer..........
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in triangles ABE AND TRIANGLE ACF
ANGLE AFC = ANGLE ABF(EACH 90) DEGREE
BE=CF(GIVEN)
& ANGLE A IS COMMON
THEREFORE TRIANGLE ABE IS CONGRUENT TO TRIANGLE ACF.
BY AAS RULE.
SO AB=AC (BY CPCT)
2. AB=AC BY (CPCT )
=> ABC IS AN ISOSCELES TRIANGLE
ANGLE AFC = ANGLE ABF(EACH 90) DEGREE
BE=CF(GIVEN)
& ANGLE A IS COMMON
THEREFORE TRIANGLE ABE IS CONGRUENT TO TRIANGLE ACF.
BY AAS RULE.
SO AB=AC (BY CPCT)
2. AB=AC BY (CPCT )
=> ABC IS AN ISOSCELES TRIANGLE
Answered by
1
BE=CF
<BAE=<CAB
<BAE=<CAF
REASON
given side
common side
each 90 degree
AB=AC ( BY CPCT)
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