Question

please answer 16th question

Answer 1

Initial rate of formation of [D] =  d [D]/dt = proportional to [A] between experiments (I) and (IV).  

Again between experiments II and III, d [D]/dt = rate of formation of [D] is proportional to square of [B].  As, [B] is doubled, [D] is 4 times.  

Hence, we get:     d [D] / dt  = k [A]^1 [B]^2
         0.006/60sec  = k * 0.1 * 0.1^2 
     =>  k =  0.1 / (mol L^-1 sec) 

rate law :    [D]_t  = 0.1 * [A] * [B]^2  *  t  + [D]_0     in  mol/L.          

[D]_0 = initial concentration of D in mol/L at t = 0.    here  t is in sec.