Question

please answer 16th question​

Answer 1

$a = \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \: \: \: \: \: \: \: b = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ \\ a + b = \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } + \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\a + b = \frac{( { \sqrt{3} - \sqrt{2} })^{2} + ( { \sqrt{3} + \sqrt{2} })^{2} }{3 - 2} \\ a + b = 2(3 + 2) = 10 \\ \\ ab = 1 \\ \\ {a}^{2} + {b}^{2} = ( {a + b})^{2} - 2ab \\ = (10) ^{2} - 2 \times 1 \\ = 100 - 2 \\ 98$